Question

The half-life of a certain radioactive material is 38 days. An initial amount of the material has a mass of 497 kg. Write an exponential function that models the decay of this material. Find how much radioactive material remains after 4 days. Round your answer to the nearest thousandth. (1 point) A ; 462.029 kg B ; 0.087 kg C ; 1.040 kg D ; 0 kg

Answer 1

It is the 1st equation at the top. 

Reason: First check the equations to check that the initial amount is 497 kg. You can do this by setting x = 0 into all of the equations. The 3rd and 4th equations evaluate to 2 when x = 0 and so you can eliminate the bottom 2 equations immediately. Equation # 2 does not work since the half-life value of 1.040 kg is way to small (significantly smaller than half of 497 kg). 

You can check that equation # 1 is the right one, by setting x = 0 and getting 

y = 497*(1/2)^[(1/38) * 0] = 497 

so the initial amount is 497 

Also check that there is 1/2 the amount at time 38 (since the half-life is 38 days) 

y = 497 * (1/2)^[(1/38) * 38] = 248.5 

248.5 kg is half of 497 and so this checks out for equation # 1. 

Since we know equation # 1 is good, now we evaluate at x = 4 to get 

y = 497 * (1/2)^[(1/38) * 4] = 462.029 

so our answer to the thousandth places is 462.029 kg.

Answer 2

The Final amount of the given material that have half life of 38 days is 462.029 kg.

Given Here,  

Initial amount = 497 kg

Half life = 38 days

Final amount after 4 days = ?

Final amount after 4 days,

$y = 497 \times \dfrac 12^{(1/38) \times 4} \\\\y = 462.029$

Therefore, the Final amount of the given material that have half life of 38 days is 462.029 kg.

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