3 consecutive positive integers: x, x + 1, and x + 2
x(x+1) = 5(x+2) - 5
x^2 + x = 5x + 10 - 5
x^2 - 4x - 5 = 0
(x + 1)(x - 5) = 0
x + 1 = 0; x = -1
x - 5 = 0; x = 5
solutions are x = -1 and x = 5
However, consecutive positive integer only so x = 5 is the smallest positive integer here
answer
the smallest of 3 consecutive positive integers is 5
