Let x be the number of white marbles and y be the number of blue marbles.
So, [tex]x+y=79[/tex]
Also, [tex]x = 4y-6[/tex] since "the number of white marbles is 6 less than 4 times the number of blue marbles"
We will solve the above system o two equation:
Using the value of x from the second equation in the first equation we get:
[tex](4y-6)+y=79\\5y=79+6\\5y=85\text{ then }y=\frac{85}{5}=17\\x=79-17=62[/tex]
Conclusion: there is 62 white marbles and 17 blue marbles.