Question

Element “yellowium” has three naturally occurring isotopes. Below are the masses and relative abundance of each isotope. Find the average atomic mass of yellowium. yellowium-15 15.012 amu 14.23% yellowium-17 16.988 amu 33.48% yellowium-19 19.177 amu 52.29%

Answer 1

To find average atomic mass, multiply each isotope's atomic mass with its relative abundance and add it all up.

15.012*0.1423 + 16.988*0.3348 + 19.177*0.5229 = 17.851 (5 s.f.)