Respuesta :
We begin with the Turner Middle School:
Ratio of students to teachers: [tex] \frac{620}{31} [/tex]
Green Middle School:
Ratio of students to teachers: [tex] \frac{950}{38} [/tex]
Let check that we cannot form a proportion:
[tex] \frac{620}{31}=20\text{ and } \frac{950}{38}=25[/tex]
The two ratios are not equals so we cannot form a proportion.
Let x be the number of teachers that Green have to hire in order to make the two ratios equal. We get the equation:
[tex] \frac{950}{38+x}=\frac{620}{31}\text{ and we solve the equation like this:}\\38+x=\frac{950\times31}{620}=47.5 \text{ and then:}\\x=47.5-38=9.5 [/tex]
The Green school need to hire 9 teachers.
Part-to-whole ratio:
Turner Middle School:
[tex] \frac{620}{31+620} [/tex]
Green Middle School:
[tex] \frac{950}{38+950} [/tex]
Ratio of students to teachers: [tex] \frac{620}{31} [/tex]
Green Middle School:
Ratio of students to teachers: [tex] \frac{950}{38} [/tex]
Let check that we cannot form a proportion:
[tex] \frac{620}{31}=20\text{ and } \frac{950}{38}=25[/tex]
The two ratios are not equals so we cannot form a proportion.
Let x be the number of teachers that Green have to hire in order to make the two ratios equal. We get the equation:
[tex] \frac{950}{38+x}=\frac{620}{31}\text{ and we solve the equation like this:}\\38+x=\frac{950\times31}{620}=47.5 \text{ and then:}\\x=47.5-38=9.5 [/tex]
The Green school need to hire 9 teachers.
Part-to-whole ratio:
Turner Middle School:
[tex] \frac{620}{31+620} [/tex]
Green Middle School:
[tex] \frac{950}{38+950} [/tex]