Respuesta :

Pond B is the snwer with a denisty of 134 geese per acre

Answer:

Option B is correct.

Pond B  has the greatest population density of resident geese

Step-by-step explanation:

Unit rate defined as the rates are expressed as quantity as 1 such as 3 meter per seconds or 5 miles per hour.

From the given table;

In Pond A:

Population of geese = 88

Area(in acres) = 1.1

Then;

[tex]\text{Population Density of resident geese per acres} = \frac{88}{1.1} = 80[/tex]

Similarly for Pond B:

[tex]\text{Population Density of resident geese per acres} = \frac{175}{1.3} = 134[/tex]

For Pond C:

[tex]\text{Population Density of resident geese per acres} = \frac{192}{1.5} = 128[/tex]

For Pond D:

[tex]\text{Population Density of resident geese per acres} = \frac{204}{2} = 102[/tex]

Therefore, the greatest population density of resident geese is in Pond B i.,e 134 Population per acres

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