Question

When a 57-gram piece of aluminum at 100oC is placed in water, it loses 735 calories of heat while cooling to 30oC. Calculate the specific health capacity of the aluminum

Answer 1

Answer:

specific heat capacity of aluminium is 0.184 Calroie/ gram-K.

Explanation:

As we know that heat transferred to a given material to change its temperature is given as

$Q = ms\Delta T$

here we know

Q = heat given = 735 calorie

m = mass = 57 gram

initial temperature = 100 degree C

final temperature = 30 degree C

now by above formula we will have

$735 = 57(s)(100 - 30)$

$s = 0.184 \frac{cal}{g-K}$