y < 4x - 2......u have a slope of 4.....u have a y int (where the line crosses the y axis) at (0,-2)......and u have a < sign....meaning it is a dashed line shaded below the line
and if u want to find ur x int (where the line crosses the x axis) sub in 0 for y and solve for x...disregarding the inequality sign
y = 4x - 2
0 = 4x - 2
-4x = -2
x = -2/-4
x = 1/2.....so ur line crosses the x axis at (1/2,0)
so ur graph is : graph 3
========================
y > -x + 3.....u have a slope of -1....u have a y int at (0,3)....ur inequality sign is >....meaning it is a dashed line, because there is no equal sign...and it is shaded above the line since it is greater then
ur x int is :
y = -x + 3
0 = -x + 3
x = 3......x int at (3,0)
ok..I am having a problem with this one because none of ur graphs match this inequality...because ur line will cross the x axis at 3...and none of ur graphs show this
===================
y < -2......when u have y = a number (or <,>) this will be a horizontal line....it will go thru -2 all the way across....and since it has a < sign, it will be a dashed line with shading under the line.
so ur graph is : graph 2
