Question

An object is dropped from the top of a tower with a height of 1130 feet. neglecting air​ resistance, the height of the object at time t seconds is given by the polynomial negative 16t squared plus 1130. find the height of the object at t equals 7 seconds

Answer 1

So you can solve this like this


So we are told that height = -16t^2+1130 right?
So to find the height at t seconds we use the formula.
Now we are told that t(time)=7 right?
So we substitute the t with 7 to get the height.
So we get h = -16(7)^2 +1130 right?
So 7 squared is 49 right?
Multiplieng by -16 gives us -784 right?
And adding 1130 gives us 340 right?
So the answer is 340
Ok?
The only thing is this is physically impossible because gravity does not attract objects that fast.
So this probably is the answer since it is a maths question so laws of gravity does not matter

Answer 2

Answer:

The height of the object at t = 7 seconds is 346 meters.

Step-by-step explanation:

Given that, an object is dropped from the top of a tower with a height of 1130 feet. Its height as a function of time is given by :

$h(t)=-16t^2+1130$.........(1)

Where

t is in seconds

We need to find the height of the object at t = 7 seconds

Put the value of t = 7 seconds in equation (1) as :

$h(7)=-16(7)^2+1130$

h (7) = 346 meters

So, the height of the object at t = 7 seconds is 346 meters. Hence, this is the required solution.