Question

Does anyone know how to solve this ?

Find the exact values of the indicated trigonometric functions. Write fractions in lowest terms. Right triangle ACB is shown where segment AC is fourteen units, segment CB is forty eight units and segment BA is fifty units. Find sin B and tan B.

Answer 1

sinB=AC/AB=14/50=7/25
tanB=AC/BC=14/48=7/24

Answer 2

Answer: The exact values of indicated trigonometric functions are:

$\sin B=\frac{7}{25}\\\\and,\\\\\tan B=\frac{7}{24}$

Step-by-step explanation:

Since we have given that

ACB is a right angled triangle,

AC = 14 units

CB = 48 units

BA = 50 units

For sin B ,we will use "SOH" :

$\sin B=\frac{AC}{AB}\\\\\sin B=\frac{14}{50}\\\\\sin B=\frac{7}{25}$

similarly,

For tan B, we will use "TOH" :

$\tan B=\frac{Perpendicular}{Hypotenuse}=\frac{AC}{CB}\\\\\tan B=\frac{14}{48}\\\\\tan B=\frac{7}{24}$

Hence, The exact values of indicated trigonometric functions are:

$\sin B=\frac{7}{25}\\\\and,\\\\\tan B=\frac{7}{24}$