Question

what is the mass of 3.62X10^24 molecules of methanol

Answer 1

n(CH₃OH)=3,62·10²⁴/6·10²³ 1/mol = 6,033 mol
m(CH₃OH) = 6,033 mol · 32 g/mol (molar mass) = 193,06 g.

Answer 2

Answer:

192.42 g  [tex] CH_ {3} OH [/ tex]

Explanation:

The chemical formula of methanol is [tex] CH 3 OH [/ tex]

we calculate the molecular mass of the compound

C 12 g / mol

H 4 (1 g / mol)

Or 16 g / mol

[tex] (12 + 4 + 16) g / mol = 32 g / mol [/ tex]

We know that 1 mole of [tex] CH 3 OH [/ tex] has [tex] (6.02) 10 {23} [/ tex] molecules of [tex] CH 3 {OH] / and these have a mass of 32 g.

Now we calculate the mass of [tex] 3.62 /cdot10 {24} [/ tex] molecules of [tex] CH 3 OH [/ tex]