Question

What is the constant of variation, k, of the direct variation, y = kx, through (–3, 2)?

Answer 1

To solve for this, use your points to plug them into the x and y values knowing that the x value in the point is -3 and the y value is 2. When you plug in the points, you should get this:

2=k(-3)

Then, because the question asks to solve for the constant of variation, or k, divide both sides by -3 to solve for k. This would get you to your answer,

k=-2/3

Answer 2

The value of the constant of variation is $k=\dfrac{-2}{3}$ in the equation $y=kx$ such that it is passing through the cordinate $(-3,2)$.

The given equation is $y=kx$ such that it is passing through the cordinate $(-3,2)$.

Substitute the value of the parameters in the given equation to evaluate the value of the constant of variation as-

$y=kx\\2=k\times (-3)\\k=\dfrac{-2}{3}$

Hence, the value of the constant of variation is $k=\dfrac{-2}{3}$ in the equation $y=kx$ such that it is passing through the cordinate $(-3,2)$.

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