Question

`suppose you were tasked with producing some nitrogen monoxide (a.k.a. nitric oxide). i'm sure this is often requested of you. you can do it by combusting ammonia (be careful!). the equation would be as follows: 4nh3 + 5o 2→ 4no + 6h2o. if you form 3.50 mol of water, how much no forms?
a. 2.33 mol.
b. 4.00 mol.
c. 4.50 mol.
d. 6.75 mol.
e. none of the above

Answer 1

n(H₂O):n(NO)=6:4(3:2), n(NO)=2·3,5mol÷3=2,33mol
So it is a).

Answer 2

Answer:

$2.33molNO$

Explanation:

Hello,

Based on the given information, NO moles are found by stating the following mole-mole relationship, by taking into account that 4 moles of water react with 4 moles of NO:

$n_{NO}=3.50molH_2O*\frac{4molNO}{6molH_2O} =2.33molNO$

Best regards