Answer:
Answer is 1/12
Step-by-step explanation:
sample space of rolling a die is={1,2,3,4,5,6}
A: rolling a 5 on the black die
A:{5}
hence, P(A)=1/6
B: rolling a number less than 4 on red die
B:{1,2,3}
hence, P(B)=3/6
A∩B: rolling a 5 on the black die and a number less than 4 on the red die
Since, both events are independent
Hence, P(A∩B)=P(A)×P(B)
           =1/6×3/6
            =1/12
hence, probability of rolling a 5 on the black die and a number less than 4 on the red die is 1/12