1. If a tRNA molecule has an anticodon which reads CAG, what was the codon on the mRNA molecule?

1) AUG
2) GTC
3) UAG
4) GUC


2. The pedigree chart below shows the individuals in a family who exhibit a certain trait. Based on the information in the chart, what are the chances that a second child born to couple 4-5 in the third generation will show the trait? (2 points)

A diagram of a pedigree chart. At the top of the chart are two individuals: one indicated by a green circle and one by a green square. At the next level down, the green circle is paired with a black square and the green square is paired with a black circle. From the green circle/black square pairing, there are three offspring: a green circle, a green square, and a black square. From the green square/black circle pairing, there are eight offspring: three black circles and four black squares. Two of the black squares are identical twins. One of the black circles is paired with another black square. This pairing produced one green circle.


a) 25 percent
b) 50 percent
c) 100 percent
d) 0 percent

Respuesta :

The answer of the first question is option "4", "GUC".
The genetic code comprises of 64 triplets of nucleotides. These triplets are called codons.With three special cases, every codon encodes for one of the 20 amino acids utilized as a part of the blend of proteins. That delivers some excess in the code: the majority of the amino acids being encoded by more than one codon.

The answer of second question is "50 percent".

The infection legacy design depicted above shows Sex linked recessive legacy design and in a cross between two heterozygous people there is a half or 50% possibility for the second child destined to be influenced. 

Answer:

the answer for the second question is 25%

Explanation:

This is because both parents show the dominant trait, but the one child shows the recessive trait. This means that both parents are heterozygous which gives the child a 25% chance to get the trait.

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