victorburi123p16y23
victorburi123p16y23
19-12-2017
Mathematics
contestada
solve for x: log5(3×-1)=2
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tynollette
tynollette
19-12-2017
If 5 is the base, 3(x-1) is the argument:
3x-1=5²
3x=26
x=26/3
If 5 is with 3x-1, that is, if 5(3x-1) is the argument, and the base is 10:
5(3x-1)=10²
3x-1=20
3x=21
x=7
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