Answer: [tex]3x^3-8x^2-61x+6[/tex].
Step-by-step explanation: Given expression [tex](x - 6)(3x^2 + 10x - 1)[/tex].
We need to multiply those binomial and trinomial.
First we would multiply x by all terms in given trinomial and then we would multiply -6 by all terms in given trinomial .
Therefore,
[tex](x - 6)(3x^2 + 10x - 1)=x(3x^2 + 10x - 1)-6(3x^2 + 10x - 1)[/tex]
[tex]=3x^3 +10x^2-x -18x^2-60x+6[/tex]
Now, combining like terms [tex]10x^2-18x^2 = -8x^2[/tex], [tex]-x-60x = -61x[/tex] , we get
[tex]3x^3-8x^2-61x+6[/tex].
Therefore, the product of [tex](x - 6)(3x^2 + 10x - 1)[/tex] is [tex]3x^3-8x^2-61x+6[/tex].
