Question

What is the inverse of h? h(x) = 6x + 1

A) h-1(x) = 6x - 1
Eliminate
B) h-1(x) = 6x + 1
C) h-1(x) =
x
6
- 1
D) h-1(x) =
1
--
6
(x - 1)

Answer 1

The answer is (x-1)/6. This is found by switching h(x) and x in the original equation, then solving for h(x) (which you can just write as "y" when solving).