Question

A frog jumps with a velocity of 3.2 m/s at an angle of 25 degrees above horizontal. What is the vertical component of its velocity?

Answer 1

Hello! Now, in order to figure this out, it is better to use a Cartesian plane system. Now, this line has a velocity of 3.2m/s and it is at an angle of 25 degrees above the horizontal. If you draw that on the Cartesian plane system, it is a diagonal line. In order find the vertical component of its velocity. Think of it as a triangle, where the velocity you are given is the hypotenuse. Since we are only given the velocity and the angle, we can use trigonometry to figure out the vertical component, in this case y-component of the velocity. You can take the velocity and multiply that by the sin of 25 degrees in order to get you the vertical component. Which will be 1.4m/s

Answer 2

Answer:

1.35m/s

Explanation:

This is done by locating the position or velocity of the frog in space and resolving the force.

Since the velocity 3.2m/s is at 25° above the horizontal, the vertical component of the velocity can be gotten by resolving the force to the positive y axis to give Vy = V sin(theta)

Given V = 3.2m/s

theta = 25°

Vy = 3.2sin25° (since the angle is at 25°above the horizontal I.e in the positive plane

Vy = 1.35m/s