Question

What is output by the following code?

int a [] = {64 , 66 , 67 , 37 , 73 , 70 , 95 , 52 , 81 , 82};

for (int i = 0; i < a.length; i++) {
a[i] = a[i] / 10;
}

for (int i = 0; i < a.length; i++) {
System.out.print(a[i] + " ");
}


1. 7 7 7 4 8 8 10 6 9 9
2. 6 6 6 3 7 7 9 5 8 8
3. 5 7 8 8 4 1 6 3 2 3
4. 2 4 5 2 2 8 6 8 1 2
5. 4 6 7 7 3 0 5 2 1 2

Answer 1

When numbers are divided, the integer portion is kept and the remainder is disregarded (meaning 10/9 would return 1). Following this format, we get the answer of 6 6 6 3 7 7 9 5 8 8. 
I also see that this program can be optimized because you use the same for loop twice, and both of them manipulate list elements in some way. A more optimized program would be:

int a [] = {64 , 66 , 67 , 37 , 73 , 70 , 95 , 52 , 81 , 82};

for (int i = 0; i < a.length; i++) {
  a[i] = a[i] / 10;
  System.out.print(a[i] + " ");
}

Or maybe you don't need to store the list values for later on. You could do:

for (int i = 0; i < a.length; i++) {
  System.out.print(a[i] / 10 + " ");
}

In any situation, your answer is choice 2.