Respuesta :
If the intial count was 100,000 bacteria, after one hour 90% decrease => 10 % stands => 100,000*0.1 bacetria. After two hours 90% decrease => 10% stands => 100,000*0.1^2. After three hours, they stand 100,000 * 0.1^3. After four hours, 100,000*0.1^4 and after five hours 100,000*0.1^5 = 1 bacteria. Answer: 1 bacteria. If the inital count is different you just have to muliply the inicial count time (0.1^n) to get the number of bacteria after n hours, and if the number of hours is 5, then the factor is (0.1^5).
For this case we have a function of the form:
[tex] y = A * (b) ^ x
[/tex]
Where,
A: initial amount of bacteria:
b: decrease rate
x: time in hours
Substituting values we have:
[tex] y = 100 * (0.90) ^ x
[/tex]
After 5 hours we have:
[tex] y = 100 * (0.90) ^ 5
y = 59.049
[/tex]
Rounding to the nearest whole number:
[tex] y = 59
[/tex]
Answer:
the bacterium count after 5 hours was:
[tex] y = 59 [/tex]