Respuesta :
3 roads...a, b and c
b = 3a.....a = 1/3b
c = 2b.....b = 1/2c.....
a ------|
b ------|--------|------|
c ------|--------|------|------|------|------|
so a is 1/6 of the total road <===
if road b is 7 miles longer the a...
b = 3a....b = a + 7
a + 7 = 3a
7 = 3a - a
7 = 2a
7/2 = a
3.5 = a
b = 3a
b = 3(3.5)
b = 10.5
c = 2b
c = 2(10.5)
c = 21 <=====road C is 21
b = 3a.....a = 1/3b
c = 2b.....b = 1/2c.....
a ------|
b ------|--------|------|
c ------|--------|------|------|------|------|
so a is 1/6 of the total road <===
if road b is 7 miles longer the a...
b = 3a....b = a + 7
a + 7 = 3a
7 = 3a - a
7 = 2a
7/2 = a
3.5 = a
b = 3a
b = 3(3.5)
b = 10.5
c = 2b
c = 2(10.5)
c = 21 <=====road C is 21
The fraction of the total length of the road is 1/10 the to the length of a and the value of c = 21 units.
Data;
- b = 3a
- c = 2b
Fraction of the total road is length of a
Let's try to find the total length of the road.
[tex]b = 3a\\c = 2b\\b = c/2\\c/2 = 3a\\c = 6a[/tex]
Let's solve in terms of a
[tex]a + 3a + 6a = 10a[/tex]
The length of the road in terms of a is 10a
The fraction of the total road is the length of a
[tex]x = 10a\\a = \frac{1}{10}\\ x = length of the road[/tex]
1/10 is the fraction of a to the total length of the road.
b)
If b = 7 + a, c = ?
[tex]b = 7 + a \\c = 2b\\c = 2(7+a)\\c = 14 + 2a[/tex]
but c = 6a
[tex]6a = 14 + 2a\\4a= 14\\a = 14/4\\a = 7/2[/tex]
substitute the value of a
[tex]c = 14 + 2a\\c = 14 + 2(7/2)\\c = 14 + 7\\c = 21 units[/tex]
From the calculations above, the fraction of the total length of the road is 1/10 the to the length of a and the value of c = 21 units.
Learn more on fractions here;
https://brainly.com/question/11562149