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The margin of error is proportional to [tex]\frac{1}{ \sqrt{n} }[/tex] where n is the sample size. therefore for the M.E. to decrease by a factor of one fourth, the sample size must increase by a factor of [tex]4^{2}=16.[/tex].
The answer is: the sample size must increase by 16 times.

16 times the sample size have to be increased to decrease the margin of error by a factor of one fourth.

Step-by-step explanation:

We know that margin of error is inversely proportional to square root of sample size n,

[tex]\rm ME\;\alpha \;\dfrac{1}{\sqrt{n} }[/tex]

So to decrease the margin of error by a factor of one fourth we have to increase the sample size by a factor of [tex]4^2[/tex].

16 times the sample size have to be increased to decrease the margin of error by a factor of one fourth.

For more information, refer the link given below

https://brainly.com/question/23012921?referrer=searchResults

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