Question

Given: ∆DEK, DE = EK

EF −∠ bisector of ∠E
m∠DEF = 44°, DK = 16
Find: KF, m∠DEK,
m∠DFE

Answer 1

Answer:

KF=8, m<DEK=88degrees, m<DFE=90 degrees

Step-by-step explanation:

Since we already know that DK is 16 you would just have to /2 to get KF=8

m<DEK=88degrees because we already know half of the angle because EF is a bisector. so 44*2=88

m<DFE=90degrees because since EF is a bisector it split it right down the middle meaning it would be equal to 90degrees.

Hope this helps! :)

Answer 2

• KF= 8
• ∠DEK= 88°
• ∠DFE= 90°

What is bisector?

A line that divides the line or angle into two different or equal parts.

Given: ∠DEF = 44°, DK= 16

Since EF is bisector of angle E, then

∠DEF=∠FEK

∠FEK=44

So, ∠DEK= ∠DEF+ ∠FEK

               = 44+44= 88°

EF is a bisector divide angle middle which equals to 90°.

∠DFE=90°

Now, Since EF is bisector

KF= DK/2

   =16/2

KF= 8

Learn more about bisector here:

https://brainly.com/question/13792156

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