Question

A piece of wood is cut into three pieces in the ratio 2:3:5. If the longest piece is 15 in longer than the shortest piece, find the lengths of the piece of wood.

Answer 1

5/10x = 2/10x + 15
5/10x - 2/10x = 15
3/10x = 15
x = 15 * 10/3
x = 150/3
x = 50

2/10(50) = 100/10 = 10 in. ....shortest piece
3/10(50) = 150/10 = 15 in .....middle piece
5/10(50) = 250/10 = 25 in .....longest piece

Answer 2

The required length of the piece of wood is 10;15;20.

Given that,

A piece of wood is cut into three pieces in the ratio of 2:3:5.

If the longest piece is 15 in longer than the shortest piece,

We have to determine,

The lengths of the piece of wood.

According to the question,

A piece of wood is cut into three pieces in the ratio of 2:3:5.

First piece = 2x

Second piece = 3x

Third piece = 5x

Total length of the wood = 2x + 3x + 5x = 10x

If the longest piece is 15 in longer than the shortest piece,

Then, a new length of longest piece = 5x+ 15

$5x = 2x + 15\\\\5x - 2x = 15\\\\3x = 15\\\\x = \dfrac{15}{3}\\\\x = 5$

Then, The length of the piece of wood is,

First wood = 2x = 2(5) = 10

Second wood = 3x = 3(5) = 15

Third wood = 5x = 5(5) = 25

Hence, The required length of the piece of wood is 10;15;20.

To know more about Ratio click the link given below.

https://brainly.com/question/11234923