Question

Ow many coulombs of charge are needed to produce 35.2 mol of solid zinc?

Answer 1

Answer: Zn(2+) + 2e(-) -------> Zn 1 mole of Zn is deposited by 2F of electricity ... so 48.9 mole of Zn will be deposited by 48.9 X 2F = 97.8 F of electricity... as 1F = 96500 C so 97.8 F = 97.8 X 96500 = 9437700 C of electricity...

Answer 2

Answer:

6.79 × 10⁶ c

Explanation:

Zn can be produced from the electrolysis of an aqueous solution of a Zn salt. The reduction reaction is:

Zn²⁺(aq) + 2 e⁻ → Zn(s)

We can establish the following relations.

• 1 mol of Zn is produced when 2 moles of e⁻ are gained.
• 1 mole of e⁻ has a charge of 96468 c (Faraday's constant).

The charge needed to produce 35.2 mol of Zn is:

$35.2molZn.\frac{2mole^{-} }{1molZn} .\frac{96468c}{1mole^{-}} =6.79 \times 10^{6} c$