We solve for n of N₂ gas from the ideal gas equation:
PV=nRT
n = PV/RT
n = (1.78 atm)(60.3 L)/(0.08206 L-atm/mol-K)(30 + 273 K)
n = 4.32 mol N₂
Through stoichiometric calculations,
Mol NaN₃ = 4.32 mol N₂ * 2 mol NaN₃/3 mol N₂ = 2.88 mol
Since the molar mass of sodium azide is 65 g/mol,
Mass = 2.88 mol * 65g/mol = 187.2 g NaN₃