Question

Bacteria in a pond multiplies as shown in the table. If a fungus on a tree decays at half that rate, what is the rate of decay (round to the nearest integer)?
thanks!

Answer 1

Using the formula, y=a(1=r)^x to solve for the growth rate and you find that the growth rate for the bacteria is 50%. Once this information is found, you can determine that a fungus decay at half that rate will be 25%.

Answer 2

Answer:

20%

Step-by-step explanation:

Population growth formula:

$P = P_0 \times e^{rt}$

where P is the total population after time t,  $P_0

$  is the starting population, r is the rate of growth and t is the time in hours

Solving for r:

$\frac{ln(\frac{P}{P_0})}{t}=r$

and replacing with data:

P =  22.781

$P_0$ = 4.5 (taking hour 2 as initial time)

t = 4 hours (time elapsed between initial time and time the population reach P)

$r=\frac{ln(\frac{22.781}{4.5)}{4}$

r = 0.4, that is equivalent to 40%

Then, fungus decay rate is 40%/2 = 20%