Question

With a growth rate parameter of 3.9% per hour. how many hours does it take for the size of the sample to double?

Answer 1

assume the sample size is one to begin with and after double is two.

2 = 1*(1.039)^t
2 = (1.039)^t
log(2) = log(1.039^t)
log(2) = t*log(1.039)
log(2)/log(1.039) = t

18.12 hours = t