Question

In ​ Quadrilateral ABCD ​ , AB¯¯¯¯¯∥CD¯¯¯¯¯ and m∠2=31°.

What is m∠5?




Enter your answer in the box.

Answer 1

$\text{Answer: }\angle 5=31\textdegree$

Explanation:

Since we have given that

AB║CD

and

$m\angle 2=31\textdegree$

Since we know that AB║CD

So, Alternate angles will be equal to each other and

$\angle2=\angle 5\\\angle 1=\angle 6$

So, value of angle 2 is equal to value of angle 5 i.e.

$\angle5=\angle 2=31\textdegree$

Hence ,

$\angle 5=31\textdegree$

Answer 2

The measure of m∠5 is 31 degrees.

Given that,

• The AB is perpendicular to CD.
• And, the m∠2=31°.

Based on the above information, the following information should be considered:

• The alternate angles should be equal i.e. ∠2 = ∠5 and ∠1 and ∠6.
• So, ∠5 = ∠2 = 31 degrees.

Therefore we can conclude that the measure of m∠5 is 31 degrees.

Learn more: brainly.com/question/17581080