Question

Polygon ABCD has sides with these lengths: , 5 units; , 4 units; , 4.5 units; and , 7 units. The slope of is 5, the slope of is 0.25, the slope of is -2, and the slope of is 0. The polygon is dilated from point A by a scale factor of 1.2 to form polygon A′B′C′D′. Match the slopes and lengths of the sides of polygon A′B′C′D′ to their values.

Answer 1

Well, you can start by putting the slopes and lengths on the right side (Where is says slope of A'B'). The slopes will be the same, so Slope of AB is still 5 and Slope of BC is still 0.25. When you get to the lengths, just multiply it by 1.2. The length for Length of CD is 5.4 and Length of AD is 8.4

Here's what it should look like:
Slope of A'B' ⇔ 5
Slope of B'C' ⇔ 0.25
Length of C'D' ⇔ 5.4
Length of A'D' ⇔ 8.4

Answer 2

Answer:

$Slope\ A'B'=5$

$Slope\ B'C'=0.25$

$length\ C'D'=5.4\ units$

$length\ A'D'=8.4\ units$

Step-by-step explanation:

we know that

Polygon ABCD and Polygon A'B'C'D' are similar

therefore

The slopes of the sides of polygon ABCD are the same of the slopes of the sides of polygon A'B'C'D'

and

the measurements of the sides of polygon A'B'C'D' are equal to the measurements of the sides of polygon ABCD multiply by the scale factor

we have

$scale\ factor=1.2$

so

Find the slopes of the dilated figure

$Slope\ A'B'=Slope\ AB=5$

$Slope\ B'C'=Slope\ BC=0.25$

Find the length sides of the dilated figure

Find the length side of C'D'

$length\ C'D'=scale\ factor*length\ CD$

we have

$scale\ factor=1.2$

$length\ CD=4.5\ units$

substitute

$length\ C'D'=1.2*4.5=5.4\ units$

Find the length side of A'D'

$length\ A'D'=scale\ factor*length\ AD$

we have

$scale\ factor=1.2$

$length\ AD=7\ units$

substitute

$length\ A'D'=1.2*7=8.4\ units$