Respuesta :
Let x= cost of apple and y= cost of orange:
5x+3y=3.50, 4x+5y=4.10.
So 20x+12y=14, so 20x=14-12y; 20x+25y=20.50.
Substitute for 20x in the second equation: 14-12y+25y=20.50
13y=6.50, y=0.50. But 5x=3.50-3y, so 5x=3.50-1.50=2.00 and x=0.40.
Therefore the cost of one apple is 40 cents and one orange is 50 cents.
5x+3y=3.50, 4x+5y=4.10.
So 20x+12y=14, so 20x=14-12y; 20x+25y=20.50.
Substitute for 20x in the second equation: 14-12y+25y=20.50
13y=6.50, y=0.50. But 5x=3.50-3y, so 5x=3.50-1.50=2.00 and x=0.40.
Therefore the cost of one apple is 40 cents and one orange is 50 cents.
Answer:
x= cost of apple and y= cost of orange:
5x+3y=3.50, 4x+5y=4.10.
So 20x+12y=14, so 20x=14-12y; 20x+25y=20.50.
Substitute for 20x in the second equation: 14-12y+25y=20.50
13y=6.50, y=0.50. But 5x=3.50-3y, so 5x=3.50-1.50=2.00 and x=0.40.
so the cost of one apple is 40 cents and one orange is frickiin 50
Step-by-step explanation: