Respuesta :

tetrahedral,

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Answer : The hybridization of central atom in [tex]CCl_4[/tex] is [tex]sp^3[/tex] and the shape of [tex]CCl_4[/tex] molecule is, tetrahedral.

Explanation :

Formula used :

[tex]\text{Number of electron pair}=\frac{1}{2}[V+N-C+A][/tex]

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

Now we have to determine the hybridization of the given molecule.

The given molecule is, [tex]CCl_4[/tex]

In this molecules, the central atom will be carbon not chlorine because carbon is less electronegative atom than the chlorine.

[tex]\text{Number of electrons}=\frac{1}{2}\times [4+4]=4[/tex]

The number of electron pair are 4 that means the hybridization will be [tex]sp^3[/tex]  and the electronic geometry of the molecule will be tetrahedral.

Hence, the hybridization of central atom in [tex]CCl_4[/tex] is [tex]sp^3[/tex] and the shape of [tex]CCl_4[/tex] molecule is, tetrahedral.

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