Respuesta :
I assume you mean this, even though what you wrote means something else because you did not use parentheses.
[tex] \dfrac{x-5}{x^2 - 3x - 10} \times \dfrac{x + 2}{x^2 + x - 12} =[/tex]
Factor each factorable polynomial.
[tex] =\dfrac{x-5}{(x - 5)(x + 2)} \times \dfrac{x + 2}{(x + 4)(x - 3)} [/tex]
Now divide the numerator and denominator by the equal terms to reduce the fraction. This is what is normally called canceling factors.
[tex] =\dfrac{1}{1} \times \dfrac{1}{(x + 4)(x - 3)} [/tex]
[tex] =\dfrac{1}{(x + 4)(x - 3)} [/tex]
[tex] \dfrac{x-5}{x^2 - 3x - 10} \times \dfrac{x + 2}{x^2 + x - 12} =[/tex]
Factor each factorable polynomial.
[tex] =\dfrac{x-5}{(x - 5)(x + 2)} \times \dfrac{x + 2}{(x + 4)(x - 3)} [/tex]
Now divide the numerator and denominator by the equal terms to reduce the fraction. This is what is normally called canceling factors.
[tex] =\dfrac{1}{1} \times \dfrac{1}{(x + 4)(x - 3)} [/tex]
[tex] =\dfrac{1}{(x + 4)(x - 3)} [/tex]
Collect like terms
(X-3x-10x+x) + (-5/x^2+2/x^2)-12
Then simplify
-11x-3/x^2-12
Let me know if that helped thanks
(X-3x-10x+x) + (-5/x^2+2/x^2)-12
Then simplify
-11x-3/x^2-12
Let me know if that helped thanks