Question

If a gas in a closed container is pressurized from 15.2 atmospheres to 19.2 atmospheres and its original temperature was 25.0oC, what would the final temperature of the gas be?

Answer 1

From  the  gay  lussac law  which  the  pressure  of  a  given  amount of  a  gas held  at  constant  volume  is  directly  proportional  to  temperature  in  kelvin.
that  is   p1/T1=P2/T2
p1=15.2 atm
P2=19.2 atm
T1=25+273=298k
T2=?
15.2/298=19.2/T2
5721.6=15.2 T2 divide both  sides by  15.2
therefore  T2=376.4k  or 103.4 degrees celsius