parallel lines have the same slope, thus if that line is parallel to the one above, it must have the same slope... .what is it anyway? let's check
[tex]\bf y=\stackrel{slope}{\cfrac{1}{2}}x\stackrel{y-intercept}{-4}\impliedby \textit{slope-intercept form}[/tex]
so, we're really looking the, for the equation of a line whose slope is 1/2, and runs through 4,5.
[tex]\bf \begin{array}{ccccccccc}
&&x_1&&y_1\\
% (a,b)
&&(~{{ 4}} &,&{{ 5}}~)
\end{array}
\\\\\\
% slope = m
slope = {{ m}}\implies \cfrac{1}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-5=\cfrac{1}{2}(x-4)
\\\\\\
y-5=\cfrac{1}{2}x-2\implies y=\cfrac{1}{2}x-2+5\implies =\cfrac{1}{2}x+3[/tex]
