Question

2 NaClO3 --> 2 NaCl + 3 O2 In order to produce 6 moles of oxygen gas, how many moles of sodium chlorate are required?
Please round final answers to the tenth position, one place after the decimal. Please only report the numerical answer.

Answer 1

the answer is that i think is 4

Answer 2

Answer : The number of moles of sodium chlorate required are, 4 moles

Solution : Given,

Moles of oxygen gas = 6 moles

The given balanced reaction is,

$2NaClO_3\rightarrow 2NaCl+3O_2$

From the given balanced reaction, we conclude that

As, 3 moles of oxygen gas produces from 2 moles of sodium chlorate

So, 6 moles of oxygen gas produces from $\frac{2}{3}\times 6=4$ moles of sodium chlorate

Therefore, the number of moles of sodium chlorate required are, 4 moles