Answer-
[tex]\boxed{\boxed{y=4}}[/tex]
Solution-
Properties of the diagonals of a rectangle,
- The two diagonals are congruent (same length).
- Each diagonal bisects the other.
- Each diagonal bisects the other.
So using the first property, length of diagonal AC and BD will be same
[tex]AC=BD[/tex]
And using second property,
[tex]BD=2\cdot BX[/tex]
Hence,
[tex]AC=2\cdot BX[/tex]
Given that,
AC = 4y and BX = y + 4
Putting the values,
[tex]\Rightarrow 4y=2\cdot (y + 4)[/tex]
[tex]\Rightarrow 4y=2y + 8[/tex]
[tex]\Rightarrow 4y-2y=8[/tex]
[tex]\Rightarrow 2y=8[/tex]
[tex]\Rightarrow y=4[/tex]
Therefore, y=4