Question

The centers for disease control and prevention reports that the rate of chlamydia infections among american women ages 20 to 24 is 2791.5 per 100,000. take a random sample of three american women in this age group. the probability that at least one of them has a chlamydia infection is

Answer 1

The probability that a randomly selected woman in the age group has the infection is:
$\frac{2791.5}{100000}=0.0279$
The probability that none of the women in the sample has the infection is:
$(1-0.0279)^{3}=0.919$
Therefore the probability that one or more of the women in the sample has the infection is: 1 - 0.919 = 0.081.
The answer is 0.081.

Answer 2

Answer:

0.081

Step-by-step explanation:

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