Starting at sea level, a submarine descended at a constant rate to a depth of −4/5 mile relative to sea level in 3 minutes. What was the submarine's depth relative to sea level after the first minute? Enter your answer as a fraction, in simplest form, in the box.

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Answer:

[tex]\texttt{Submarine's depth relative to sea level after the first minute =}-\frac{4}{15}miles[/tex]

Step-by-step explanation:

Starting at sea level, a submarine descended at a constant rate to a depth of −4/5 mile relative to sea level in 3 minutes.

Total time = 3 minutes

[tex]\texttt{Total depth descended in 3 minutes =}-\frac{4}{5}miles[/tex]

We need to find what was the submarine's depth relative to sea level after the first minute,

[tex]\texttt{Depth descended in per minute =}\frac{-\frac{4}{5}}{3}=-\frac{4}{15}miles[/tex]

[tex]\texttt{Submarine's depth relative to sea level after the first minute =}-\frac{4}{15}\times 1=-\frac{4}{15}miles\\\\\texttt{Submarine's depth relative to sea level after the first minute =}-\frac{4}{15}miles[/tex]

Answer:

-3/20

Step-by-step explanation:

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