Hi there!
The question is asking us to find the equation for a line parallel to y = 4x - 9 that passes through the point (-5, 3). To do this, we need to take the slope, which is 4, and take the point, (-5,3) and plug it back into the slope-intercept form to find the value of b (the y-intercept).
y = mx + b; y = 3, x = -5, m = 4
Substitute values;
3 = 4(-5) + b
3 = -20 + b
23 = b
Therefore, when we create the new equation, we get y = 4x + 23, giving us an answer of D) y = 4x + 23. Hope this helps and have a great day!
