Question

Center=(-2,3) and radius=4. Write the equation of the circle

Answer 1

equation of a circle = (y-k)^2 + (x-h)^2 = r^2, where the center is at (h, k) and r = radius
${(y - 3)}^{2} + {(x + 2)}^{2} = 16$

Answer 2

The equation of the circle is: y²+x²-6y+4x=13

What is equation of circle?

The equation for a circle is given by:

(y-k)² + (x-h)² = r²

Where (h,k) is the center and r is the radius of the circle.

Given:

Center=(-2,3) and radius=4

equation of a circle

(y-k)² + (x-h)² = r², where the center is at (h, k) and r is the radius.

We have , h= -2, y=3 and r=4

So, equation of circle will be:

(y-3)² + (x-(-2))² = 4²

(y-3)² + (x+2)² = 4²

y²+9-6y+x²+4+4x=16

y²+x²-6y+4x=13

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