Let's figure out how long it will take to fall 75 meters, from the 1st roof to the second roof. We can assume that gravity is the only force affecting vertical velocity, so the ball starts from rest and accelerates downward at g, or -9.8m/s².
Let's find how long it takes to fall 75 meters:
s(t) = Vi + (1/2)*a*t²,
where s(t) is displacement as a function of time, Vi is initial velocity (zero), and a is acceleration. Plugging in our values:
-75 = 0 + (1/2)(-9.8)(t²) Multiply both sides by 2/-9.8
15.3 = t² Take the square root of both sides
t = 3.91
We need to the ball to travel 20 meters horizontally before it hits the roof in 3.91 seconds. We can assume that the horizontal velocity remains constant (a=0, Vi=V(t) for all t).
Therefore, the minimum horizontal velocity is:
D = V*t , simple distance formula, distance equals velocity times time:
20 = V * 3.91 Divide both sides by 3.91
V = 5.11
The horizontal velocity, therefore, must be at least 5.11m/s in order for the ball to reach the roof of the second building.
