Question

A farmer is experimenting with pea plants. If the farmer crosses two pea plants with round and yellow peas (genotype RrYy) how many offspring will be green and wrinkled (rryy)?

Answer 1

Answer:

The genotype of both parents is RrYy.

The possible types of gametes would be RY, Ry, rY, and ry.

The cross would produce offspring that can have one out of four types of phenotypes:

• Round and yellow seeds (1 RRYY+ 2 RrYY +2 RRYy + 4 RrYy) = 9/16
• Wrinkled and yellow seeds (3 rrYy) = 3/16
• Round and green seeds (1 RRyy + 2 Rryy) = 3/16
• Wrinkled and green seeds (rryy) = 1/16

Thus, one out of 16 offspring would have wrinkled and green seeds.

Answer 2

Answer:

1/16

Explanation: