Question

A 60 kg student is standing motionless. Approximately how much force is the floor exerting on the student?
A. 60 kg downward
B.600 N upward
C.600 N downward

Answer 1

The normal force is equal in magnitude and opposite in direction to the weight of the student.
W = m · g = 60 kg · 10 m/s² = 600 N ( downward )
N = - 600 N
Answer:
B ) 600 N upward.