Question

Write the point-slope form of the line that passes through (6, 1) and is perpendicular to a line with a slope of -3. Include all of your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution.

Answer 1

y - 1 = 1/3 (x - 6) would be your answer.
Hope this helps!!

Answer 2

Answer:

The point slope form of required line is $y-1=\frac{1}{3}(x-6)$.

Step-by-step explanation:

It is given the the required line passes through the point (6,1) and perpendicular to a line with a slope of -3.

The product of slopes of two perpendicular lines is -1.

Let the slope of required line be m.

$m\times -3=-1$

Divide both sides by -3.

$m=\frac{-1}{-3}$

$m=\frac{1}{3}$

The slope of required line is 1/3.

If a line passes through the point $(x_1,y_1)$ with sloe m, then the point slope form of the line is

$y-y_1=m(x-x_1)$

The point slope form of required line is

$y-1=\frac{1}{3}(x-6)$

Therefore the point slope form of required line is $y-1=\frac{1}{3}(x-6)$.