Answer:
The y-intercept is in the point with coordinates y = 2
(And x = 0)
Step-by-step explanation:
Given a generic line with the equation [tex]y=ax+b[/tex] the y-intercept can be calculated replacing the variable ''x'' by 0 and finding the value of ''y'' that verifies the equation.
In the exercise we haven't got the line in the form [tex]y=ax+b[/tex] but also we can calculate the y-intercept replacing x = 0 and finding the ''y'' value that verifies the equation :
[tex]2x+3y=6\\2.(0)+3y=6\\3y=6\\y=\frac{6}{3}=2 \\y=2[/tex]
We calculate the y-intercept like this because all the points that are over the y-axis have the following form (0,y) being ''y'' a real number.
For this line in particular, the y-intercept will be the point with coordinates (0,2).
