Respuesta :
Hi there!
Unfortunately, that's not the right equation. I'll help show you the proper steps.
So, first, let's define i.
i = √(-1)
Now, let's multiply -i and i
(-i)(i)
Substitute the value of i
- √(-1) * √(-1)
Let's add a parenthesis using the associative property of multiplication
- [ √(-1) * √(-1) ]
Multiplying two same square roots eliminates the square root symbol.
- (-1)
A negative of a negative is positive
= 1
Thus, a negative imaginary number multiplied with a positive imaginary number equals positive 1.
Have an awesome day! :)
Unfortunately, that's not the right equation. I'll help show you the proper steps.
So, first, let's define i.
i = √(-1)
Now, let's multiply -i and i
(-i)(i)
Substitute the value of i
- √(-1) * √(-1)
Let's add a parenthesis using the associative property of multiplication
- [ √(-1) * √(-1) ]
Multiplying two same square roots eliminates the square root symbol.
- (-1)
A negative of a negative is positive
= 1
Thus, a negative imaginary number multiplied with a positive imaginary number equals positive 1.
Have an awesome day! :)
[tex] (-i)i =-ii [/tex]Once we multiply the negative imaginary number (-i) to the positive imaginary number (i),
[tex] \left(-i\right)(i) [/tex]
[tex] \mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a [/tex]
[tex] (-i)i =-ii [/tex]
[tex] \mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c} [/tex]
[tex] ii=\:i^{1+1}=\:i^2\\ -ii=-i^2 [/tex]
[tex] \mathrm{Apply\:imaginary\:number\:rule}:\quad \:i^2=-1 [/tex]
[tex] -i^2=-(-1) [/tex]
Which is equal to 1.
so multiply a negative imaginary number (-i) by a positive imaginary number (i), it equals to positive 1.