Why is it that if you multiply a negative imaginary number (-i) by a positive imaginary number (i), it equals to positive 1? Shouldn’t it be a negative 1?

-(-1) • (-1) = -1
This is the right equation, right?

Respuesta :

Hi there!

Unfortunately, that's not the right equation. I'll help show you the proper steps.

So, first, let's define i.

i = √(-1)

Now, let's multiply -i and i

(-i)(i)

Substitute the value of i

- √(-1) * √(-1)

Let's add a parenthesis using the associative property of multiplication

- [ √(-1) * √(-1) ]

Multiplying two same square roots eliminates the square root symbol.

- (-1)

A negative of a negative is positive

= 1

Thus, a negative imaginary number multiplied with a positive imaginary number equals positive 1.

Have an awesome day! :)

[tex] (-i)i =-ii [/tex]Once we multiply the negative imaginary number (-i) to the positive imaginary number (i),

[tex] \left(-i\right)(i) [/tex]

[tex] \mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a [/tex]

[tex] (-i)i =-ii [/tex]

[tex] \mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c} [/tex]

[tex] ii=\:i^{1+1}=\:i^2\\ -ii=-i^2 [/tex]

[tex] \mathrm{Apply\:imaginary\:number\:rule}:\quad \:i^2=-1 [/tex]

[tex] -i^2=-(-1) [/tex]

Which is equal to 1.

so multiply a negative imaginary number (-i) by a positive imaginary number (i), it equals to positive 1.

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