A scientist is cooling a liquid at a steady rate. The temperature of the liquid changed by −82 1/2 °C over 2 1/5 minutes. What was the temperature change after 1 minute? Enter your answer as a mixed number, in simplest form

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Calniz
Hey there, Emily!

To solve for this one, or to find the rate per minute, we need to divide how much it changed by how long it took.
So, -82 [tex] \frac{1}{2} [/tex] divided by [tex]2 \frac{1}{5} [/tex]
But first, we need to convert the fractions into improper fractions by following the following formula
[tex]a \frac{b}{c} ---\ \textgreater \ \frac{(a*c)+b}{c} [/tex] (Just replace the letters for the numbers)
Once we turn them into improper fractions, we will get
[tex]- \frac{165}{2} [/tex] and [tex] \frac{11}{5} [/tex]
Now, we need to divide them and to do so, you have to multiply [tex]- \frac{165}{2} [/tex] by the reciprocal of [tex] \frac{11}{5} [/tex] which is [tex] \frac{5}{11} [/tex] and we get a total of [tex]- \frac{825}{22} [/tex] and simplified will be -37.5 degrees per minute.

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