Question

Supposed the population of deer in a region was 3,500 in the year 2000.since then population has grown by 3.5% annually. What will the approximate population be in the year 2020? Y=a•b^x where a is the starting amount, b is the growth rate (increasing add to 1),and x is time.

Answer 1

y = a (b^x)

1) x = 0, y = 3500

=> 3500 = a (b^0)

=> 3500 = a (1)

=> a = 3500

2) growth percent = 3.5% => growth rate = 1.035 = b

=> y = 3500 (1.035)^ x

3) year 2020 => x = 2020 - 2000 = 20

4) y = 3500 (1.035)^ 20 = 6964

Answer: 6964.